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  • Splitting an archive
  • Multi-part archive
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Stored procedures
Returns the number of parts of a given size required to split a single-part archive.
Remark: This function is available for the archives in ZIP and WDZ format only.
Example
WEBDEV - Server codeAjax
MonArchive est un zipArchive
// Ouverture d'une archive
ResOuvreArchive = MonArchive.Ouvre("C:\MesArchives\Archive.zip")
 
SI ResOuvreArchive = 0 ALORS
...
// Nombre de parties de 1,4 Mo nécessaires pour contenir l'archive
ResNbPartieNécessaire = MonArchive.NbPartieNécessaire(1400*1024)
Info("Pour découper cette archive, " + ResNbPartieNécessaire + ...
" partie(s) de 1,4 Mo sont nécessaires")
...
FIN
Syntax
<Result> = <Archive>.NbNecessaryPart(<Size of parts>)
<Result>: Integer
Number of parts of a given size required to contain an archive.
<Archive>: zipArchive variable
Name of a zipArchive variable that corresponds to the archive to use.
<Size of parts>: Integer
Size of parts in bytes. The default size is equal to 1.44 MB (1400*1024 bytes). The minimum size is equal to 300 KB for each part (300*1024 bytes).
Remarks

Splitting an archive

A multi-part archive is created by <zipArchive variable>.Split. The <zipArchive variable>.NbPartNeeded function allows you to know the number of parts needed to split the archive.

Multi-part archive

Using <zipArchive variable>.NbPartNeeded on a multi-part archive allows you to calculate the number of parts required for a new splitting.
Component: wd270zip.dll
Minimum version required
  • Version 24
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