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Stored procedures
Identifies the opacity of a pixel in an image (in an Image control) with an Alpha channel.
Linux Caution: A specific configuration is required to use this function in Linux. For more details, see The drawings.
Example
// Identify the opacity of the pixel (15, 25)
// on the "IMG_ImageDrawing" control
ResOpacity = IMG_ImageDrawing.PixelOpacity(15, 25)
Syntax
<Result> = <Image variable>.PixelOpacity(<X-coordinate> , <Y-coordinate>)
<Result>: Integer
Opacity of specified pixel (included between 0 for transparent and 255 for opaque).
<Image variable>: Image variable
Name of the Image control to be used.
<X-coordinate>: Integer
Horizontal position of pixel to use.
<Y-coordinate>: Integer
Vertical position of pixel to use.
Remarks

Coordinates

Coordinates are given in pixels with respect to the upper-left corner of the image (coordinates: (0.0)).
To retrieve the position of a mouse click in an Image control, use MouseXPos and MouseYPos.

Drawing in an image with opacity

To specify that the drawing in the image supports opacity (Alpha channel), use <Image>.StartDrawing and the dWithOpacity constant.
Component: wd280obj.dll
See also
Minimum version required
  • Version 24
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