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LastDayOfYear (Function) In french: DernierJourDeLAnnée Returns the date of the last day of the year.  New in version 2025dateSubscription is Date = "20190125"
dateEndOfYear is Date = LastDayOfYear(dateSubscription)
nNumberDaysBeforeEndOfYear is int
nNumberDaysBeforeEndOfYear = DateDifference(dateSubscription, dateEndOfYear)
Syntax
Getting the last day of the year based on a date Hide the details
<Result> = LastDayOfYear([<Date>])
<Result>: Character string Last day of the year (YYYYYMMDD) for the specified date. <Date>: Optional character string, Date or DateTime variable Date for which the last day of the year must be calculated. This date can correspond to: - a character string in YYYYMMDD format (YYYY corresponds to the year, MM to the month and DD to the day).
- a character string in YYYYMMDDHHmmSSCC format (YYYY corresponds to the year, MM to the month, DD to the day, HH to hours, mm to minutes, SS to seconds and CC to hundredths of a second (use CCC for thousandths of a second)). In this case, only the date is taken into account.
- a Date variable.
- a DateTime variable. In this case, only the date is taken into account.
If this parameter is not specified, the current date is used by default.
Finding out the last day of the year based on a year Hide the details
<Result> = LastDayOfYear(<Year>)
<Result>: Character string or Date variable Last day of the year (YYYYYMMDD). <Year>: Integer Year for which the last day must be calculated. Remarks This function is used to easily calculate date ranges.
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