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  • Drawing in an image with opacity
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Stored procedures
Identifies the opacity of a pixel in an image (in an Image control) that manages the Alpha layer.
Versions 15 and later
WINDEVJava This function is now available for Java applications.
New in version 15
WINDEVJava This function is now available for Java applications.
WINDEVJava This function is now available for Java applications.
Versions 16 and later
WINDEVLinux This function is now available for WINDEV applications in Linux.
Linux Caution: A specific configuration is required to use this function in Linux. For more details, see The drawings.
New in version 16
WINDEVLinux This function is now available for WINDEV applications in Linux.
Linux Caution: A specific configuration is required to use this function in Linux. For more details, see The drawings.
WINDEVLinux This function is now available for WINDEV applications in Linux.
Linux Caution: A specific configuration is required to use this function in Linux. For more details, see The drawings.
Example
// Identify the opacity of the pixel (15, 25)
// on the "IMG_ImageDrawing" control
ResOpacity = IMG_ImageDrawing.PixelOpacity(15, 25)
Syntax
<Result> = <Image control>.PixelOpacity(<X coordinate> , <Y coordinate>)
<Result>: Integer
Opacity of specified pixel (included between 0 for transparent and 255 for opaque).
<Image control>: Control name
Name of the Image control to use.
<X coordinate>: Integer
Horizontal position of pixel to use.
<Y coordinate>: Integer
Vertical position of pixel to use.
Remarks

Coordinates

Coordinates are given in pixels with respect to the top left corner of the image (coordinates: (0.0)).
To retrieve the position of a mouse click in an Image control, use MouseXPos and MouseYPos.

Drawing in an image with opacity

To specify that the drawing in the image supports opacity (Alpha layer), use <Image>.StartDrawing and the dWithOpacity constant.
Component: wd260obj.dll
Minimum version required
  • Version 24
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