<TreeView>.Identifier (Function)

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Retrieving the identifier of an element with management of duplicates

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<TreeView>.Identifier (Function)

In french: <Arbre>.RécupèreIdentifiant

Returns the identifier associated with an element (node or leaf) in a TreeView control.

Example of TreeView control:

Example

// Return the identifier of "Desserts" node in the "TREE_RecipeTV" TreeView control
Res = TREE_RecipeTV.Identifier("Recipes" + TAB + "Desserts")

Syntax

<Result> = <TreeView control>.GetIdentifier(<Element path>)

<Result>: Character string

Identifier of specified element,
Empty string ("") if no identifier is associated with the element or if the element does not exist.
If the identifier (defined by <TreeView>.Add or <TreeView>.Modify) is not a character string but an integer, you may have to convert the result into an integer in order to handle this identifier (Val).

<TreeView control>: Control name

Name of TreeView control to use.

<Element path>: Character string

Full path of element to use. This parameter has the following format:

"<Name of root>" + TAB + ["<Name of 1st node>" + TAB + ...
["<Name of 2nd node>" + TAB + [...]]]"<Leaf name>"

Remarks

Retrieving the identifier of an element with management of duplicates

To retrieve the identifier of the selected element taking the duplicates into account, <Element path> must correspond to the following code:

<TreeView control>.Select(True)

For example:

Trace(TREE_TreeView1.Select() + "/" + ...
TREE_TreeView1.Identifier(TREE_TreeView1.Select(True)))

Component : wd250obj.dll